44-9t^2=0

Solution for 44-9t^2=0 equation:

44-9t^2=0

a = -9; b = 0; c = +44;
Δ = b2-4ac
Δ = 02-4·(-9)·44
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{11}}{2*-9}=\frac{0-12\sqrt{11}}{-18}
=-\frac{12\sqrt{11}}{-18}
=-\frac{2\sqrt{11}}{-3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{11}}{2*-9}=\frac{0+12\sqrt{11}}{-18}
=\frac{12\sqrt{11}}{-18}
=\frac{2\sqrt{11}}{-3}
$